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let length = l , width = w ,

for a rectangle,

2l + 2w = 10w

l + w = 5w

l = 4w

Therefore , l = 4 times of w...

Thanks...

Since the formula for the perimetre of a recrengle is,

P=2w+2l

Where w= width and l= length

So if p= 10w (given) then by putting this in above eq we get,

10w=2w+2l

5w=w+l

l=4w

So length is 4 times greater than its width.

2a+2b=10a; 2b=8a; b=4a

let w be the width and l be the length Thus: 2(l+w) = 10w l+w = 5w l = 4w Thus the length is 4 times the length of the width

Hello, this is my first post in a discussion. I solved this problem by assigning the value 10 to the width on both ends of the rectangle making the overall addition of the widths ( 2W) to be 20, then I used 20 + 2L = 100 2L = 80 L = 40 40/10 = 4 It may seem strange but that's just my method. Thank you for reading.

perimeter=2(length+width) as perimeter is 10 times greater than its width so we take w=1 and p=10

10=2(length+1) 10/2=length+1 5-1= length length=4 thanks.

L = length W = width

2L + 2W = 10W

     -2W     -2W

2L = 8W

       /2         /2

L = 4W

2*(L+B)=10B OR, L+B=5B OR, L=4B OR, L/B=4

length is l and width is b

2(l+b)=10(b) 2l+2b=10b 2l=8b l=4b hence ,it is four times ....this was easy one...

I'd say 2 l +2w but l looks too much like 1 in certain fonts, so let's just say;

2L+2W=10W, then dividing both sides by 2, you have: L+W=5W, then subtracting W from both sides, you have L=4W, which gives you the answer, the length is 4 times the width in a rectangle with a perimeter 10 times its width.

let the width be x. The perimeter = 10x. since 2l + 2w = 10x, we can deduce that 2w = 2x. 10x-2x= 8x. 8x/2=4x, therefore length is 4 times the width.

Let length be $x$ and wodth be $y$ .
Then, $2\left(x + y\right) = 10y\\ \left(x + y\right) = 5y\\ x = 4y$
So, the answer is $\color{#69047E}{\boxed{4}}$ .