Geometry Fundamentals: Slope 6

Geometry Level 1

If a line has slope 10 10 and passes through the point ( 3 , 39 ) (3, 39) , what value of a a in ( 4 , a ) (4, a) makes that point lie on the line?


The answer is 49.

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2 solutions

Brilliant Mathematics Staff
Aug 1, 2020

Since the slope tells us the amount that the value of y y changes for any unit change in x x , and we can see that ( 3 , 39 ) , ( 4 , a ) (3, 39), (4, a) are one x x -unit apart, we can conclude that a a must be equal to 39 39 plus the value of the slope, 10 10 . Thus the answer is 39 + 10 = 49 39 + 10 = 49 .

Alternately, we could use the formula for slope ( m = y 2 y 1 x 2 x 2 m = \frac{y_2-y_1}{x_2-x_2} ), and substitute in all of the known values:

10 = a 39 4 3 , 10 = \frac{ a - 39}{ 4-3 },

which also shows that a = 49 a = 49 .

I put 49 49 but it says it's incorrect, @Brilliant Mathematics .

Yajat Shamji - 10 months, 2 weeks ago

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Thanks. I've made a mistake. I've updated the answer to 49 . Those who previously answered 49 has been marked correct.

Brilliant Mathematics Staff - 10 months, 2 weeks ago
Mahdi Raza
Aug 4, 2020
  • We know that a straight line has equation y = m x + c y = mx + c , hence

39 = 10 ( 3 ) + c c = 9 39 = 10(3) +c \implies c = 9

  • To find a a , we just keep f ( x ) = a f(x) = a since it is the y-cordinate

a = 10 ( 3 ) + 9 a = 49 a = 10(3) + 9 \implies \boxed{a = 49}

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