If a line has slope 1 0 and passes through the point ( 3 , 3 9 ) , what value of a in ( 4 , a ) makes that point lie on the line?
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I put 4 9 but it says it's incorrect, @Brilliant Mathematics .
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Thanks. I've made a mistake. I've updated the answer to
49
. Those who previously answered
49
has been marked correct.
3 9 = 1 0 ( 3 ) + c ⟹ c = 9
a = 1 0 ( 3 ) + 9 ⟹ a = 4 9
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Since the slope tells us the amount that the value of y changes for any unit change in x , and we can see that ( 3 , 3 9 ) , ( 4 , a ) are one x -unit apart, we can conclude that a must be equal to 3 9 plus the value of the slope, 1 0 . Thus the answer is 3 9 + 1 0 = 4 9 .
Alternately, we could use the formula for slope ( m = x 2 − x 2 y 2 − y 1 ), and substitute in all of the known values:
1 0 = 4 − 3 a − 3 9 ,
which also shows that a = 4 9 .