Equilateral
is inscribed in a circle. A point
lies on the circumference of the circle such that
and
intersect at point
. Given that
and
, find
.
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By Ptolemy, AB,PC + AC.PB = AP.BC or AP = PB + PC = 25. Now we claim by similar triangles that 1/DP = 1/PB + 1/PC and therefore, 1/DP = 1/5 + 1/20 or DP = 4. Hence, AD = 25 - 4 = 21.