Geometry problem 7 by Dhaval Furia

Geometry Level pending

A B AB is a diameter of a circle of radius 5 5 . Let P P and Q Q be two points on the circle so that the length of P B PB is 6 6 , and the length of A P AP is twice that of A Q AQ . What value is the length of Q B QB is nearest to?

8.5 8.5 9.1 9.1 7.8 7.8 9.3 9.3

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1 solution

Let A Q = x , A P = 2 x , Q B = y |\overline {AQ}|=x, |\overline {AP}|=2x,|\overline {QB}|=y .

Then x 2 + y 2 = 1 0 2 = 100 , 4 x 2 + 36 = 100 x = 4 y = 84 9.165 x^2+y^2=10^2=100,4x^2+36=100\implies x=4\implies y=\sqrt {84}\approx \boxed {9.165} .

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