In the given fig.
A parallelogram is enclosed within a quadrilateral.
Using the given elements of the fig,
Determine, angle 'x'
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48+49+y=180; y= 83 .since x+y=180; x+83=180; x= 97
y = 1 8 0 − 4 9 − 4 8 = 8 3
The sum of the interior angles of a parallelogram is 3 6 0 ∘ , so
2 x + 2 y = 3 6 0
2 x + 2 ( 8 3 ) = 3 6 0
2 x = 1 9 4
x = 9 7
49+48+x=180
x+y=180
y=48+49=97
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48 + 49 + y = 180 ; y = 103 since x + y = 180 therefore x 97