It's staring at me

Geometry Level 4

Let Δ A B C \Delta ABC be a triangle with vertices A = ( 0 , 0 ) , B = ( 6 , 0 ) , C = ( 3 , 3 3 ) , A=(0,0), B=(6,0), C=\big(3,3\sqrt{3}\big), and Δ P Q R \Delta PQR the pedal triangle of Δ A B C . \Delta ABC.

The sum of the circumradius of Δ A B C \Delta ABC and inradius of Δ P Q R \Delta PQR can be expressed as a b c \frac{a\sqrt{b}}{c} for positive integers a , b , a,b, and c , c, where a , c a,c are coprime and b b is square-free.

Find a × b × c a\times b\times c .


The answer is 30.

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2 solutions

Ahmad Saad
Nov 26, 2015

Pedal triangle is defined with respect to a point, so you have not provided enough information as yet.

Is it the pedal triangle from the center of the incircle?

Calvin Lin Staff - 4 years, 9 months ago

Since the midpoint M of AB is also (3,0), CM is the altitude of isosceles triangle CA=CB.
Slope of AC = 3 \sqrt3 , so angle CAB=60.
So ABC is equilateral side 6. R= 2 3 2\sqrt3 .
Hence pedal triangle also equilateral side 3.
Pedal inradius 1/2 its Circumradius=1/2 * 1/2 * R.
Required sum 2 3 ( 1 + 1 4 ) = 5 2 3 2\sqrt3(1+\frac 1 4)=\frac5 2*\sqrt3
a * b * c=5 * 2 * 3=30.

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