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Classical Mechanics Level 2

Two skaters A & B of mass 50 kg \textbf{kg} & 70 kg \textbf{kg} respectively stand facing each other 6 m \textbf{m} apart. They pull on light rope stretched between them. How far has each moved when they meet?

Both have moved 3m A moves 2.5m & B moves 3.5 m A moves 3.5 m & B moves 2.5 m A moves 2 m & B moves 4 m

Archiet Dev by Archiet Dev , 20, India

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1 solution

Lokesh Sharma
Jun 29, 2014

No need to solve it mathematically. Just notice that the heavier person would have travelled less than the lighter person. Alternatively, you can calculate the displacements of both using the concept of Center Of Mass .

3 Helpful 0 Interesting 0 Brilliant 0 Confused

I did it like this

ratio of movement = ratio of masses

So A = 5/12 x 6 = 2.5 m And B = 7/12 x 6 = 3.5 m

But, bigger masses have greater inertia, so it undergoes less motion.

Hence, whatever we found is correct, but reverse the results. for A and B.

That is A being the lighter one moves 3.5 m and B being the heavier one moves 2.5 m.

Awnon Bhowmik - 6 years, 11 months ago

Hey @Lokesh Sharma You Have Provided wrong link -Correct one is This

Archiet Dev - 6 years, 11 months ago

We will simply apply_ m1v1=m2v2

sachin mittal - 6 years, 11 months ago

Doesn't it depend on whether there is sufficient friction? Otherwise both should move an equal distance(?)

Rohan Hebbal - 6 years, 8 months ago

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