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Calculus Level 3

Arrange the following in descending order : 1 1 , 2 2 , 3 3 , 4 4 , 5 5 , 6 6 , 7 7 \color{#20A900}{\sqrt [1]{1},\sqrt [2]{2},\sqrt [3]{3},\sqrt [4]{4},\sqrt [5]{5},\sqrt [6]{6},\sqrt [7]{7}}

If the arrangement is of the form n 1 n 1 , n 2 n 2 , n 7 n 7 \sqrt [n_{1}]{n_{1}},\sqrt [n_{2}]{n_{2}},\ldots\sqrt [n_{7}]{n_{7}} ,find the value of n 1 n 2 n 3 n 7 \overline {n_{1}n_{2}n_{3}\ldots n_{7}} .


  • in case of 4 4 , 2 2 \sqrt[4]{4},\sqrt [2]{2} ,enter 4 4 first and then 2 2 .i.e. 42 \overline {\ldots42\ldots} .
  • This problem is created by me.
  • Have you tried the first part ?


The answer is 3425671.

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1 solution

Gabriel Vasto
Jan 24, 2019

If we define a function, f(x)=x^(1/x), we can show that f'(x)>0 only if x<e, i.e., f does have a maximum at x=e. Then, for values of x such that x<e, f will be a crescent function, and for x>e, a decrescent one. Hence, we already know that 3>4>5>6>7 (and, of course, all of this must be >1). But notice that the fourth root of 4 is exactly the same as the second root of 2, which leads us to the corret order: 3425671.

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