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Geometry Level 2

If the coordinates of the midpoints of the side of a triangle are ( 1 , 2 ) , ( 0 , 1 ) (1, 2), (0, -1) and ( 2 , 1 ) (2, -1) . then find the coordinates of its vertices.

(3, 2), (1, 2), (1, 4) (3, 2), (-1, 2), (1, -4) (3, -2), (1, -2), (1, -4) (-3, -2), (-1, -2), (-1, -4)

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2 solutions

展豪 張
May 14, 2016

Centroid of these three mid-points = centroid of original triangle
Centroid = 1 3 ( ( 1 , 2 ) + ( 0 , 1 ) + ( 2 , 1 ) ) = ( 1 , 0 ) =\dfrac 13((1,2)+(0,-1)+(2,-1))=(1,0)
Centroid cut medians into 2 : 1 2:1
The three points are
( 1 , 0 ) 2 ( ( 1 , 2 ) ( 1 , 0 ) ) = ( 1 , 4 ) (1,0)-2((1,2)-(1,0))=(1,-4)
( 1 , 0 ) 2 ( ( 0 , 1 ) ( 1 , 0 ) ) = ( 3 , 2 ) (1,0)-2((0,-1)-(1,0))=(3,2)
( 1 , 0 ) 2 ( ( 2 , 1 ) ( 1 , 0 ) ) = ( 1 , 2 ) (1,0)-2((2,-1)-(1,0))=(-1,2)

Abhiram Rao
May 4, 2016

It would be great if you could explain the mid-point theorem and provide details of the solution so that everyone can understand it. Thanks! @Abhiram Rao

Sandeep Bhardwaj - 5 years, 1 month ago

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Sure sir , I will do it.

Abhiram Rao - 5 years, 1 month ago

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Thanks! So nice of you. :)

Sandeep Bhardwaj - 5 years, 1 month ago

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