Getting stronger in titrations!

Chemistry Level 4

5.5 g of a mixture of F e S O X 4 ⋅ 7 H X 2 O \ce{FeSO4.7H2O} and F e X 2 ( S O X 4 ) X 3 ⋅ 9 H X 2 O \ce{Fe2(SO4)3.9H2O} required 5.4 mL of 0.1N K M n O X 4 \ce{KMnO4} solution for complete oxidation. The mole of hydrated ferric sulphate in mixture is P P .

Find ⌊ 1000 P ⌋ \lfloor 1000P \rfloor


The answer is 9.

Md Zuhair by Md Zuhair , 20, India

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1 solution

Suhas Sheikh
Jun 12, 2018

Trivial by Law of Equivalences Note equivalent weight of the ferrous sulphate hydrate would be equal to its molecular weight due to n-factor being 1 (Fe(2+) is oxidised to Fe(3+) )

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IS everything trivial for you bro?

Md Zuhair - 2 years, 12 months ago

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Not really XD

Suhas Sheikh - 2 years, 11 months ago

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