Gibbs free energy equilibrium constant 1

Chemistry Level pending

The Δ G ° Δ G° of the following chemical reaction is − 104.18 -104.18 kJ: 3 NO ( g ) → N 2 O ( g ) + NO 2 ( g ) . 3 \text{NO} (g) \rightarrow \text{N}_{2}\text{O} (g) + \text{NO}_{2} (g). Then what is the equilibrium constant of this reaction at 25.0 25.0 °C?

1.8 × 1 0 18 1.8 \times 10^{18} 1.8 × 1 0 13 1.8 \times 10^{13} 42.03 42.03 − 42.03 -42.03

Krishna Singh by Krishna Singh , 22, India

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1 solution

Suhas Sheikh
Jun 11, 2018

Plug DelG= -RTlnK And find K Trivial problem

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