Give me Five !!

11 × 3 × 5 = 1 5 1 × 3 × 5 × 7 = 10 5 1 × 3 × 5 × 7 × 9 = 94 5 1 × 3 × 5 × 7 × 9 × 11 = 1039 5 \begin{array}{c}1 1\times 3 \times 5 =1{\color{#3D99F6}5} \end{array} \\ 1\times 3 \times 5 \times 7 = 10{\color{#3D99F6} 5} \\ 1\times 3\times 5\times 7 \times 9 =94{\color{#3D99F6}5} \\ 1\times 3\times 5\times 7 \times 9 \times 11= 1039{\color{#3D99F6}5}


Is it true that the unit digit of n ! ! n!! is always 5 if n > 3 n>3 is an odd number ?

Inspiration

Notation: ! ! !! denotes double factorial notation . For example : 7 ! ! = 7 × 5 × 3 × 1 7!! = 7\times 5\times 3\times 1 and 4 ! ! = 4 × 2 4!! = 4\times 2 .

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1 solution

Kellen Atkins
Jul 25, 2018

If n!! is an odd number and n > 3 then n!! = 5 * the product of odd numbers. Since the product of any odd numbers is an odd number and 5 * an odd number will end in 5 n!! will always end with a 5.

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