Giving it JEE touch #3

A ball of radius R is uniformly charged with the volume density p. The flux of the electric field strength vector across the ball's section formed by the plane located at a distance ( r < R) from the centre of the ball is given by : N ρ π r ( R 2 r 2 ) / 9 Ɛ Nρπr(R^{2}-r^{2})/9Ɛ What is the value of N ?


The answer is 3.

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1 solution

Vineet Kumar
Jun 1, 2015

Plz some 1 provide me a solution to this problem!

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