N 2 + N = N 3 - N
What is the product of all the numbers N could be?
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N = 0 is a solution. Hence the product must be 0.
There are three solutions of the equation N 2 + N = N 3 - N namely ( 2 , − 1 , 0 ) and 2 × ( − 1 ) × ( 0 ) = 0
There are three solutions to the above equation: 2, -1, and 0. Therefore, their product is 2 ∗ 0 ∗ − 1 , which is equal to 0 .
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The easiest solution to find is N=0, by moving all the terms to one side and factoring an N out. Now we do not need to find the other solutions because 0 times anything is 0 .