Go crazy with variable (number 1)

Algebra Level 1

If $(x+A)(x+B)$ is equal to $(x+C)(x+D)$ , express $x$ in terms of $A,B,C$ and/or $D$ .

(AB-CD)/(A+B-C-D) 1/(AB-CD) 1/(A+B-C-D) (A+B-C-D)/(AB-CD) (CD-AB)/(A+B-C-D)

1 solution

Poo La
Jan 11, 2016

THE SOLUTION GOES LIKE THIS.....................

(x+A)(x+B)=(x+C)(x+D)

x^2+Ax+Bx+AB=x^2+Cx+Dx+CD THE TWO x^2 WILL BE CANCELLED.......... THUS GIVING US...............

Ax+Bx+AB=Cx+Dx+CD

BY FACTORING,WE GET............. (A+B)x+AB=(C+D)x+CD

BY TRANSPOSING TERMS,WE GET.............. (A+B)x-(C+D)x=CD-AB

BY DISTRIBUTING THE NEGATIVE SIGN, (A+B-C-D)x=CD-AB

AND BY DIVIDING BOTH SIDES BY (A+B-C-D) WE CAN GET THE VALUE x=(CD-AB)/(A+B-C-D) AS OUR FINAL ANSWER............... THANK YOU.........:-)

Not sure about this question, all I can work out is that I need a number 2

Kyran Gaypinathan - 5 years, 3 months ago