go quadra go!!!

Algebra Level 3

Solve this quadratic equation:- $x^2- (3 \sqrt{2}-2i)x-6 \sqrt{2}i=0$ find the roots where $i$ is iota, the imaginary number whose square is negative one.

2(2^0.5) and -i 3(2^0.5) and -2i 6(2^0.5) and -4i 4(2^0.5) and -i

1 solution

Elijah L
May 26, 2020

The equation can be factored into $(x+2i)(x-3\sqrt{2}) = 0$ , hence the roots are $\boxed{-2i \textnormal{ and } 3\sqrt{2}}$ .

go quadra go!!!

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