God

There are 3 Gods and 3 wells.
Condition No. 1 take some flowers
Condition No. 2 drop all the flowers in well No.1 and flowers will get doubled , out of which put some flowers to the God No.1
Condition No. 3 Drop the balance flowers which from condition No.2 in Well No.2 , it will be doubled , out of which put some flowers to the God No.2,
Condition No. 4 drop the Balance flowers from condition No.3 in well No.3, it will be doubled , put all the flowers to the God No.3 and there will be NO BALANCE FLOWERS.
Condition No. 5, put flowers to the each God so that they must be in equal number.
What is number of flowers taken by the man before dropping in the first well ?


The answer is 7.

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2 solutions

Ganesh Alat
Feb 28, 2014

let X be the flowers , in well 1 it becomes 2X , give Y flowers to god1, remaining 2X-Y get doubled to 4X-2Y after subtracting the Y flower it became 4X-3Y Again in well 3 it became 8X-6Y & all the flowers given to god 3 which is Y so that, 8X-6Y=Y, 8X=7Y, there fore there should be 7 floers should be drop in the well & 8 flower given to the god.

Sanskar Kushwah
Feb 26, 2014

If we will take 7 flowers it will get doubled in well 1 and will become 14 We will drop 8 flowers At God 1 Remaining will be 6 we will double it in well 2 it will become 12 again we will drop 8 flowers at God 2 and remaining will be 4 it will get double in well 3 and become 8 flowers we will drop all 8 flowers and we left nothing.

Let x is the no of flowers taken by the man before first well.... And a is the no of flowers to each god..

Mathematically equation is 2(2(2x-a)-a)-a=0

Solving the equation then we get x=7a/8... Let a=8....so x=7...

ajinkya Kulkarni - 7 years, 1 month ago

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