Godzilla cubes
Number Theory
Level
3
what is the sum of the digits of 9,999,999,999^3?
The answer is 180.
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
1 solution
sum of the digits of cube of 99^3 = (970299)36 in which 36 = 18 x no.of digits of the original number
sum of the digits of cube of 999^3 = (997002999)54 in which 54 = 18 x no.of digits of the original number.
similarly 9,999,999,999^3 = 18 x 10 = 180