16 going 17

Solve the linear Diophantine equation 2011 x + 2017 y = 1 2011x + 2017y = 1 for integer solution such that x x is least natural number. Submit your answer as x + y x + y .


The answer is 1.

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1 solution

Rajen Kapur
Jan 14, 2016

2017 2011 = 1 + 1 335 + 1 6 \frac{2017}{2011}=1 +\cfrac{1}{335 +\cfrac{1}{6}} , ignoring insignificant 1 6 \frac{1}{6} in comparison to large 335 the given fraction is marginally less than 336 335 \frac{336}{335} . Equating this to x y \frac{x}{-y} , we get x = 336, y = -335 and x + y = 1 x + y = 1

You cannot "ignore" the numbers over there. This is a question of number theory and not of numerical analysis. Instead, by euclidean algorithm, the values of x and y can be easily determined.

Anand Chitrao - 5 years, 5 months ago

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The intention behind ignoring insignificant fraction is to emphasize the fact that G.I.F. is used here to arrive at a close ratio with smaller numerator and denominator. In my opinion it is a tool of algebra, neither number theory nor numerical analysis.

Rajen Kapur - 5 years, 5 months ago

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Try to solve the equation 2012 x + 2017 y = 1 with your method.

Ricardo Moritz Cavalcanti - 9 months, 3 weeks ago

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