Going to the movies

For his birthday, Max got 4 new movies as gifts. If Max watches each movie once, how many different orders could he have watched them in?


The answer is 24.

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8 solutions

Darliane Silva
Sep 5, 2013

Assiste cada filme UMA VEZ. Logo,temos no 1º dia 4 possibilidades,no 2º dia 3 possibilidades, no 3ºdia 2 possibilidades e no 4º dia 1 possibilidade. Ou seja: 4 x 3 x 2 x 1 = 24

Se você colocasse em inglês ganharia mais votos

Ewerton Cassiano - 7 years, 9 months ago
John Palm
Sep 3, 2013

Max has : 4 probability in the first turn, 3 in the next turn, 2 in the next turn, and finally just 1 left. so he could watch it with 4x3x2x1 different orders = 24 orders

What do you mean by "4 probability in the first turn"? Be mindful of the choice of word that you are using, as that can cause confusion.

Calvin Lin Staff - 7 years, 9 months ago

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How he can't repeat the sequence he used the factorial

Ewerton Cassiano - 7 years, 9 months ago
Aniruddha Tayade
Sep 2, 2013

As Max has got 4 new movies as gifts...

so he can watch in 24 different orders....

1 \times 2 \times 3 \times 4 = 24

there are 4 movies and we have to arrange them in way that there would be no repetition and this can be done in 4! ways

4!=4x3x2x1 Multiply them all. 4!=24 Therefore,24 is the answer. Got it?

Gabriel Merces
Sep 5, 2013

Ele Pode Ir de Diversas Maneiras sem se Importar a Ordem Assim Você Só Calcula o Número de Maneiras pelo Número de Ingressos :

4! = 4 \times 3 \times 2 \times 1 = 24

Usa em inglês

Ewerton Cassiano - 7 years, 9 months ago
Ewerton Cassiano
Sep 3, 2013

For answer he question, we only need to do the fatorial of the number 4. 4! = 4 3 2*1 4!= 24

Use only Factorial -=-=-

Kim Joshua Desposado - 7 years, 9 months ago

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Yes

Ewerton Cassiano - 7 years, 9 months ago

I'm sorry, I only wanted to put the product of the numbers

Ewerton Cassiano - 7 years, 9 months ago
Petr Chloupek
Sep 2, 2013

4 * 3 * 2 * 1 = 4! pick one random from 4 than pick one from the remaining 3 and then one from the remaining 2

4!

Kumar Pankaj Sahai - 7 years, 9 months ago

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This question is very easy

Ewerton Cassiano - 7 years, 9 months ago

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