Golden Ratio 2: A circle, a square, and Φ.

Geometry Level 1

A circle has the circumference 8 π ( 2 + 20 ) 2 \frac{8π√(2+√20)}{2} . Its area can be expressed as a π Φ aπΦ , where a is an integer. Determine the value of a 2 a^2 .

Note: Φ Φ represents the golden ratio.


The answer is 256.

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1 solution

Yashas Ravi
Apr 1, 2018

Φ Φ , or the golden ratio is 1 + 5 2 \frac{1+√5}{2} . Recognizing that Φ Φ is in the answer for the area, and to obtain the radius you have to take the principal root of the area, we should perform Φ \sqrt{Φ} . By simplification and radicalizing the denominator, Φ = \sqrt{Φ} = ( 2 + 20 ) 2 \frac{√(2+√20)}{2} . Since the circumference is 2 r π 2rπ , where r r is the radius, we can divide the circumference length by 2 π to obtain the radius. However, it is a good idea to keep the expression ( 2 + 20 ) 2 \frac{√(2+√20)}{2} so we can obtain π π in our area. Dividing by 2 π gives us 4 4 ( 2 + 20 ) 2 \frac{√(2+√20)}{2} , and substituting this for the formula for the area of a circle, π r 2 πr^2 , we get the area to be 16π 1 + 5 2 \frac{1+√5}{2} . Since 1 + 5 2 \frac{1+√5}{2} = Φ = Φ , our answer is in the form a π Φ aπΦ , where a = 16 a=16 . The question asks for a 2 a^2 , so a 2 = 1 6 2 = 256 a^2=16^2=256 , which is our final answer.

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