The harmonic mean of two numbers a and b is 4. It is also given that 2 A + G 2 = 2 7 , where A and G are the arithmetic mean and geometric mean of a and b respectively.
Find the numbers a and b .
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Given that harmonic mean:
H a 1 + b 1 2 a + b 2 a b A G 2 ⟹ G 2 = 4 = 4 = 4 = 4 = 4 A A = 2 a + b and G = a b
Therefore,
2 A + G 2 2 A + 4 A 6 A ⟹ A = 2 7 = 2 7 = 2 7 = 2 9 ⟹ a + b = 9 ⟹ G 2 = a b = 4 A = 1 8
Then we have:
a + b a 2 + a b a 2 − 9 a + 1 8 ( a − 3 ) ( a − 6 ) = 9 = 9 a = 0 = 0 Multiply both sides by a Note that a b = 1 8
⟹ { a = 3 a = 6 ⟹ b = 6 ⟹ b = 3
Therefore, a and b are 3 and 6 .
Harmonic mean is n/(1/a + 1/b) where n = number of numbers, in this case 2.
So 2/(1/a + 1/b) = 4.
Therefore, 2/4 = 1/a + 1/b = 1/2.
1/4 + 1/8 = 3/8
1/9 + 1/12 = 7/36
1/6 + 1/9 = 5/18
1/3 + 1/6 = 3/6 = 1/2 ✔️
As check Arithmetic mean A = (3+6)/2=4.5 and 2*A = 9.
Geometric mean G = sqrt(3*6) = sqrt(18) so G^2 = 18.
Sum = 27 ✔️
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The given numbers are a , b . For two numbers a , b : A = 2 a + b , G 2 = a b , H = a + b 2 a b
Harmonic Mean H M = a + b 2 a b = 4 ⟹ 2 a b = 4 ( a + b ) ⟹ a b = 2 ( a + b )
2 A + G 2 = 2 7 ⟹ 2 × 2 a + b + a b = 2 7
⟹ ( a + b ) + 2 ( a + b ) = 2 7 (since a b = 2 ( a + b )
⟹ ( a + b ) = 9
Now, from algebra we know that ( a + b ) 2 − ( a − b ) 2 = 4 a b
⟹ ( a − b ) 2 = ( 9 ) 2 − 2 × 4 ( a + b ) = 8 1 − 7 2 (since 2 a b = 4 ( a + b ) )
⟹ ( a − b ) = ± 3
If a − b = + 3 by solving a + b = 9 a n d a − b = + 3 we get :
⟹ a = 6 , b = 3
If a − b = − 3 by solving a + b = 9 a n d a − b = − 3 we get :
⟹ a = 3 , b = 6
Therefore, the required numbers are 3 and 6