Equation in Progressions

Algebra Level 2

The harmonic mean of two numbers a a and b b is 4. It is also given that 2 A + G 2 = 27 2A + G^2 = 27 , where A A and G G are the arithmetic mean and geometric mean of a a and b b respectively.

Find the numbers a a and b b .

6 and 9 4 and 8 3 and 6 9 and 12

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3 solutions

Ram Mohith
Jun 17, 2018

The given numbers are a , b a,b . For two numbers a , b : A = a + b 2 , G 2 = a b , H = 2 a b a + b a,b : \space A = \dfrac{a + b}{2}, \space G^2 = ab, \space H = \dfrac{2ab}{a + b}

Harmonic Mean H M = 2 a b a + b = 4 2 a b = 4 ( a + b ) a b = 2 ( a + b ) HM = \dfrac{2ab}{a + b} = 4 \implies 2ab = 4(a + b) \implies ab = 2(a + b)

2 A + G 2 = 27 2 × a + b 2 + a b = 27 2A + G^2 = 27 \implies 2 \times \dfrac{a + b}{2} + ab = 27

( a + b ) + 2 ( a + b ) = 27 \implies (a + b) + 2(a + b) = 27 (since a b = 2 ( a + b ) ab = 2(a + b)

( a + b ) = 9 \implies (a + b) = 9

Now, from algebra we know that ( a + b ) 2 ( a b ) 2 = 4 a b (a + b)^2 - (a - b)^2 = 4ab

( a b ) 2 = ( 9 ) 2 2 × 4 ( a + b ) = 81 72 \implies (a - b)^2 = (9)^2 - 2 \times 4(a + b) = 81 - 72 (since 2 a b = 4 ( a + b ) 2ab = 4(a + b) )

( a b ) = ± 3 \implies (a - b) = \pm 3

If a b = + 3 a - b = +3 by solving a + b = 9 a n d a b = + 3 a + b = 9 \space and \space a - b = +3 we get :

a = 6 , b = 3 \implies a = 6, b = 3

If a b = 3 a - b = -3 by solving a + b = 9 a n d a b = 3 a + b = 9 \space and \space a - b = -3 we get :

a = 3 , b = 6 \implies a = 3, b = 6

Therefore, the required numbers are 3 and 6 \color{#20A900}\text{Therefore, the required numbers are 3 and 6}

Given that harmonic mean:

H = 4 2 1 a + 1 b = 4 2 a b a + b = 4 A = a + b 2 and G = a b G 2 A = 4 G 2 = 4 A \begin{aligned} H & = 4 \\ \frac 2{\frac 1a + \frac 1b} & = 4 \\ \frac {\color{#3D99F6}2\color{#D61F06}ab}{\color{#3D99F6}a+b} & = 4 & \small {\color{#3D99F6} A = \frac {a+b}2} \text{ and }\color{#D61F06} G = \sqrt{ab} \\ \frac {\color{#D61F06}G^2}{\color{#3D99F6}A} & = 4 \\ \implies G^2 & = 4A \end{aligned}

Therefore,

2 A + G 2 = 27 2 A + 4 A = 27 6 A = 27 A = 9 2 a + b = 9 G 2 = a b = 4 A = 18 \begin{aligned} 2A + \color{#D61F06}G^2 & = 27 \\ 2A + \color{#D61F06}4A & = 27 \\ 6A & = 27 \\ \implies A & = \frac 92 & \small \color{#3D99F6} \implies a+b = 9 \implies G^2 =ab = 4A = 18 \end{aligned}

Then we have:

a + b = 9 Multiply both sides by a a 2 + a b = 9 a Note that a b = 18 a 2 9 a + 18 = 0 ( a 3 ) ( a 6 ) = 0 \begin{aligned} a+b & = 9 & \small \color{#3D99F6} \text{Multiply both sides by }a \\ a^2 + \color{#3D99F6} ab & = 9a & \small \color{#3D99F6} \text{Note that }ab = 18 \\ a^2 - 9a + \color{#3D99F6} 18 & = 0 \\ (a-3)(a-6) & = 0 \end{aligned}

{ a = 3 b = 6 a = 6 b = 3 \implies \begin{cases} a = 3 & \implies b = 6 \\ a = 6 & \implies b = 3 \end{cases}

Therefore, a a and b b are 3 and 6 \boxed{\text{3 and 6}} .

Roger Erisman
Mar 5, 2019

Harmonic mean is n/(1/a + 1/b) where n = number of numbers, in this case 2.

So 2/(1/a + 1/b) = 4.

Therefore, 2/4 = 1/a + 1/b = 1/2.

1/4 + 1/8 = 3/8

1/9 + 1/12 = 7/36

1/6 + 1/9 = 5/18

1/3 + 1/6 = 3/6 = 1/2 ✔️

As check Arithmetic mean A = (3+6)/2=4.5 and 2*A = 9.

Geometric mean G = sqrt(3*6) = sqrt(18) so G^2 = 18.

Sum = 27 ✔️

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