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Calculus Level 4

n = 2 1986 ( 1 1 k = 0 n k ) \prod _{ n=2 }^{ 1986 } \Bigg({ 1-\frac { 1 }{\displaystyle \sum _{ k=0 }^{ n }{ k } } } \Bigg)

If the product above equals to a b \frac a b for some relatively coprime positive integers a , b a,b , find b a b-a .

This problem belongs to this set


The answer is 1985.

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1 solution

Ramesh Goenka
Mar 4, 2015

Moderator note:

Great! Is it possible to solve by telescoping series of products if the k = 0 n k \displaystyle \sum_{k=0}^n k is replaced by k = 0 n k 2 \displaystyle \sum_{k=0}^n k^2 ? How about other sums of powers? Why or why not?

This is exactly how I did this. Good job, Sir :)

Trung Đặng Đoàn Đức - 6 years, 3 months ago

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