Good problem

Algebra Level 1

( 1 + 1 4 ) ( 1 + 1 5 ) ( 1 + 1 6 ) ( 1 + 1 7 ) = ? \left(1 + \dfrac14\right) \left( 1 + \dfrac15\right) \left( 1 + \dfrac16\right)\left( 1 + \dfrac17 \right) = \ ? \


The answer is 2.

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2 solutions

( 1 + 1 4 ) × ( 1 + 1 5 ) × ( 1 + 1 6 ) × ( 1 + 1 7 ) \Rightarrow \left(1 + \dfrac14\right) ×\left( 1 + \dfrac15\right)× \left( 1 + \dfrac16\right)×\left( 1 + \dfrac17 \right)

= ( 5 4 ) × ( 6 5 ) × . . . . . × ( 8 7 ) =\left(\dfrac{5}{4}\right)×\left(\dfrac{6}{5}\right)×.....×\left(\dfrac{8}{7}\right)

8 4 = 2 \Rightarrow \dfrac{8}{4}=\boxed{2}

don't understand

nyem lam - 5 years, 2 months ago

how you get 8/4

nyem lam - 5 years, 2 months ago

understood no problem

nyem lam - 5 years, 2 months ago
Revanth Kaparthi
Jan 16, 2016

By solving that,we be(5/4)(6/5)(7/6)(8/7)=8/4=2

Or you could do 9 +10

James D - 5 years, 4 months ago

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