Good warm up problem

Calculus Level pending

In case you are just waking up or you just got on brilliant, here is a great problem to warm up your mind with. Also, I'm starting a new set of problems called "the warm ups problem sets." Made of Relatively easy or medium difficulty problems. I will be posting probably 1 or more per day.

The minimum value of x 4 2 + 2 x 3 3 4 x 2 8 x + 2000 \frac{x^4}{2}+\frac{2x^3}{3}-4x^2-8x+2000 can be written as a/b for co-prime integers a,b. Find a+b.


The answer is 5947.

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1 solution

Trevor Arashiro
Sep 16, 2014

We take the derivative of this function, and are left with 2 x 3 + 2 x 2 8 x 8 = 0 2x^3+2x^2-8x-8=0 . We factor this to (x+1)(x+2)(2x-4)=0. Then we plug in the answers to see what yields the minimum value. And we find that it occurs at x=2.

Is there any way to skip the plug and chug step?

X= -2 MINIMUM VALUE

Aareyan Manzoor - 6 years, 8 months ago

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