True or False?
The perimeter of a right-angled triangle of a given hypotenuse is at maximum when the triangle is isosceles.
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Let's say the sides are a , b and c , where c is the longest side.
Assume the 2 unknown angles are x and y .
By Trigonometry Formula, we obtain:
s i n x = c a
c o s x = c b
[SIMPLIFY] a = c s i n x and b = c c o s x
Perimeter P = a + b + c
[SUBSTITUTE] P = c s i n x + c c o s x + c
P ′ = c c o s x − c s i n x [DIFFERENTIATE]
At maximum, P ′ = 0 :
0 = c c o s x − c s i n x
c c o s x = c s i n x
c o s x s i n x = 1
t a n x = 1 , where x < 9 0 d e g r e e s
x = 4 5 d e g r e e s , then y = 1 8 0 − 4 5 − 9 0 = 4 5 d e g r e e s
We get 9 0 d e g r e e s , 4 5 d e g r e e s , 4 5 d e g r e e s -> Isosceles right-angled triangle
[PROVEN]