Grade 8 - Algebra #4

Algebra Level 3

A stationery shop sells only one kind of notebook, with the list price at 120 % 120\% of the production cost, such that the total net profit would be $ 28 \$28 if unchanged. But it didn't sell well, so they decided to take 10 % 10\% off from the list price of it when there were exactly 100 100 notebooks left. The actual total net profit was $ 23.2 \$23.2 .

Given that the production cost doesn't change at all and the stock doesn't get replenished, how many notebooks did they sell?


Detail: Ignore all of the other factors aside from notebook selling. Examples of things to ignore - employee paycheck, rent of the shop, food expenses, etc.

Image source: ENGLISH@ Fernand Léger, "Notebook: Page n°1"

This problem is a part of <Grade 8 - Algebra> series .


The answer is 350.

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1 solution

Boi (보이)
Jul 9, 2017

Let the production cost be x x , and the total amount of notebooks they sold be y y .

Then the production cost, no matter the changes of the list price, is x y xy .

And the expected total net profit before the price change was 1.2 x y x y = 0.2 x y = 28 1.2xy-xy=0.2xy=28

x y = 140 A xy=140~\cdots~\boxed{A} .


List price Sold stocks Gross profit (=Production cost + Net profit)
Before price change 1.2 x 1.2x y 100 y-100 1.2 x ( y 100 ) 1.2x(y-100)
Price change × 0.9 \times0.9 - -
After price change 1.08 x 1.08x 100 100 108 x 108x
Overall - - x y + 23.2 xy+23.2

From the table above, we see that 1.2 x ( y 100 ) + 108 x = x y + 23.2 1.2x(y-100)+108x=xy+23.2 .

0.2 x y 12 x = 23.2 0.2xy-12x=23.2

x y 60 x = 116 B xy-60x=116~\cdots~\boxed{B} .


Subtract B \boxed{B} from A \boxed{A} , and you get 60 x = 24 60x=24 , which leads to x = 0.4 x=0.4 .

Substituting to A \boxed{A} , we get y = 350 y=350 .

Therefore, the stationery shop sold 350 \boxed{350} notebooks.

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