Grand Ping Pong Tournament

Two people are competing with each other during a Ping-Pong tournament, whoever wins four matches first wins (No tie game). How many possible scenarios are there? (Ex: WWLWW and LWWWW count as different scenarios)


The answer is 70.

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2 solutions

Kevin Xu
Sep 16, 2019

As an upgrade version of Ping Pong Tournament the idea is similar. \\

The game may last from 4(One person WWWW) up to 7 (One person lose three wins four games) \\ So we break down the possible scenarios into 4 games, 5 games, 6 games, and 7 games. \\ - We only count the ways a person can win the game then times it by two for the sake of simplicity. \\ - We also assume the person wins the last game, otherwise, the game would end early before reaching the total number of matches (Ex: WWWWLL is not possible).

WWWW 1
_ _ _ _ W C 4 3 = 4 C^3_4=4
_ _ _ _ _W C 5 3 = 10 C^3_5 = 10
_ _ _ _ _ _ W C 6 3 = 20 C^3_6 = 20

( 1 + 4 + 10 + 20 ) × 2 = 70 (1 + 4 + 10 + 20) \times 2 = 70

Richard Desper
Sep 17, 2019

Similar to logic of best-of-5 competition, there are ( 7 4 ) \binom{7}{4} ways for Player 1 to win and ( 7 4 ) \binom{7}{4} ways for Player 2 to win.

And, yes, this generalizes. If two players compete until one has won n n matches, there are 2* ( 2 n 1 n ) \binom{2n-1}{n} possible tournaments.

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