If a graph is simple and hypohamiltonian, which of these statements must be true?
A. It is hamiltonian
B. It is nonplanar
C. It is 3-connected
Definitions:
A
simple
graph has no loops or multiple edges.
A
hamiltonian cycle
of a graph is a cycle that goes through all vertices of the graph.
A graph is
hamiltonian
if it has a hamiltonian cycle.
A graph is
hypohamiltonian
if it has at least two vertices, and removing any one vertex of the graph leaves it hamiltonian.
A graph is
3-connected
if it has at least four vertices, and removing any two vertices from the graph still leaves it connected.
A graph is
planar
if it can be drawn on the plane without any two edges crossing.
A graph is
nonplanar
if it is not planar.
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Only C is true.
A is false. A hypohamiltonian graph might not be hamiltonian. In fact, the common definition of hypohamiltonian graph is exactly that: graphs that are not hamiltonian, but becomes hamiltonian on removing any vertex. A simple example (also the smallest) is the Petersen graph .
B is also false. A hypohamiltonian graph can easily be planar; a simple example is K 4 , the complete graph on four vertices. It is planar: take a triangle and a point inside it, and join each pair of points. It is hypohamiltonian: removing any vertex leaves a triangle which is trivially hamiltonian.
C is true. Note that after removing any one vertex, the remaining graph is hamiltonian. Thus removing one more vertex will still leave the graph connected (take a hamiltonian cycle in the graph; this connects all vertices, and since it's a cycle, removing any one vertex still leaves a path that connects all vertices). Thus removing any two vertices still leaves the graph connected, so it is 3-connected.