Suppose there is a class with 30 students. Is it possible that 9 students have 3 friends each in the class, 11 have 4 friends each, and 10 have 5 friends each?
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
Consider the students as vertex of a graph and their friends as degree of that vertex.
So , total degree of all vertices is = ( 9 × 3 ) + ( 1 1 × 4 ) + ( 1 0 × 5 ) = 1 2 1
But in graph theory sum of degree of vertices is twice the number of edges i.e. even.But here it is odd
That's why not possible.