Graphing can fool you 2

Lets play with graph

• First of all let's plot $\left\lfloor 2|x| \right\rfloor$

we know that the end points of $y=\left\lfloor |x| \right\rfloor$ represent $y=x$ with horizontal length of 1 unit

$\therefore$ end points of $\left\lfloor 2|x| \right\rfloor$ will represent $y=2x$ with horizontal length halved (quite obvious, you are multiplying each $x$ by $2$ )

Similarly we can plot $\left\lceil x^{ 2 } \right\rceil$ with extreme(it is ceil not floor) end points representing $y=x^2$

Combining both of them

we can easily see $6$ ranges and $3$ integer solutions