Gravitation in Depth

A planet of radius R = 1 10 × ( radius of the Earth ) R = \frac1{10} \times (\text{ radius of the Earth}) has the same mass density as Earth. Scientist dig a well of dept R 5 \frac R 5 on it and lower a wire of same length and of linear mass density 1 0 3 kgm 1 10^{-3} \text{ kgm}^{-1} into it. If the wire is not touching anywhere, find the force applied at the top of the wire by a person holding in place.

Details and Assumptions:

  • The radius of the Earth as 6 × 1 0 6 m 6\times 10^6\text{ m} .

  • The acceleration due to gravity on Earth is 10 ms 2 10\text { ms}^{-2} .

96 N 96 \text{ N} 120 N 120 \text{ N} 150 N 150 \text{ N} 108 N 108 \text{ N}

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