GRAVITATION

Classical Mechanics Level pending

What should be the length of the day so that the weight of the body on the equator of earth becomes zero ? (radius of earth=6400 km and g =10m/s^2 )

7.8 hrs 5 hrs 1.4 hrs 24 hrs

Soham Saha by Soham Saha , 20, India

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1 solution

Soham Saha
Dec 28, 2014

T = 2*22/7 * r^1/2 / g^1/2

0 Helpful 0 Interesting 0 Brilliant 0 Confused

did not understand

Ashutossh Gupta - 6 years, 5 months ago

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Kepler's Third Law. T^2/r^3 = 4 pi^2 / GM T^2=(4 pi^2 r^3)/g R^2 T^2=(4*pi^2 * r) /g

Brandon Teoh - 5 years, 9 months ago

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