Gravitational field

Which of the following is true for a uniform solid sphere of mass M M and radius b ? b ?

Gravitational field at r=0 is equal to 0. For r<b, gravitational field decreases as r increases. Gravitational field at r=b is G M / b 3 . \text{ is } GM/b^{3}. For r>b, gravitational field increases as r increases.

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1 solution

Kshitij Johary
Jul 20, 2014

Refer the diagram below:

Alt text Alt text

At a distance r from the centre of the sphere, the gravity g is given by g = G m r 2 g=\frac { Gm}{ { r }^{ 2 } } where m is the mass of uniform solid sphere of radius r, g is the gravity and G is the Gravitational Constant.

Now, m = 4 3 π r 3 ρ m=\frac { 4 }{ 3 } \pi r^{ 3 }\rho where ρ \rho is the density of the solid sphere. g = G 4 3 π r 3 ρ r 2 = G 4 3 π r ρ \Rightarrow g=\frac { G\frac { 4 }{ 3 } \pi { r }^{ 3 }\rho }{ r^{ 2 } } \\ \quad \quad \quad =\quad G\frac { 4 }{ 3 } \pi { r }\rho When r=0, g = 0.

Hence, gravitational field at r=0 will be 0.

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