Gravity Pulley problem

A body of mass m 1 =12kg \text{m}_{ 1 }\text{=12kg} placed on a smooth horizontal table. It is connected to a string which passes over a friction less pulley and carries another body of mass m 2 =8kg \text{m }_{ 2 }\text{=8kg} at the other end. Calculate the acceleration produced in the bodies when the nail fixed on the table to hold m 1 \text{m}_{ 1 } is removed.

Details and Assumptions :

1) Take acceleration due to gravity as 10m s 2 \text{10m s }^{ -2 }

1 8 2 125 16 12 4 64

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1 solution

Chew-Seong Cheong
Mar 11, 2015

When the nail is removed, the force on the two bodies is:

F = m 2 g = 8 × 10 = 80 N F = m_2g = 8 \times 10 = 80N

The acceleration a a produced by F F is given by:

F = ( m 1 + m 2 ) a a = 80 12 + 8 = 4 m s 2 F = (m_1+m_2)a \quad \Rightarrow a = \dfrac {80}{12+8} = \boxed{4}ms^{-2}

Perfect again! And a wonderful job again!

Sravanth C. - 6 years, 3 months ago

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