Gravity Gravity with protons

Classical Mechanics Level 2

Find the gravitational force between two protons kept at a separation of 1 femtometre.

DETAILS AND ASSUMPTIONS:

1) Fine, take the mass of a proton as $1.67\times10^{-27}$

1.86\times10^{34}

1.14\times10^{-34}

2.98\times10^{-34}

2.69\times10^{-34}

1.86\times10^{-34}

1.66\times10^{-34}

2.98\times10^{34}

1 solution

Caleb Townsend
Feb 21, 2015

The law of universal gravitation: $F = G\frac{m_1\times m_2}{r^2}$ Substitute $m_1 = m_2 = 1.67\times 10^{-27},$ $r = 1\times 10^{-15}$ and $G = 6.67\times 10^{-11}.$ $F = 6.67\times 10^{-11}\frac{(1.67\times 10^{-27})^2}{(10^{-15})^2}$ $F = \boxed{1.86\times 10^{-34}}$

Gravity Gravity with protons

1 solution

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