A wooden block of mass 0.9 kilograms is suspended from the ceiling of a room by thin wires.
A bullet of mass 0.1 kilograms moving with a horizontal velocity of strikes the block and sticks to it.
What is the height to which the block rises?
Details and assumptions:
To make the calculations easier take the acceleration due to gravity as
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It is given that:
By conservation of momentum, the velocity of the wooden block and bullet together v 1 after the bullet strikes the wooden block is given by:
m 2 v 0 = ( m 1 + m 2 ) v 1 ⇒ 0 . 1 ( 1 0 0 ) = ( 0 . 9 + 0 . 1 ) v 1 ⇒ v 1 = 1 0 m s − 1
By conservation of energy, we have the height h the block rises is given by:
2 1 ( m 1 + m 2 ) v 1 2 = ( m 1 + m 2 ) g h
⇒ 2 1 ( 1 ) ( 1 0 0 ) = ( 1 ) ( 1 0 ) h ⇒ h = 5 m