Gravity Suspension

A wooden block of mass 0.9 kilograms is suspended from the ceiling of a room by thin wires.

A bullet of mass 0.1 kilograms moving with a horizontal velocity of 100 m s 1 100 ms^{-1} strikes the block and sticks to it.

What is the height to which the block rises?

Details and assumptions:
To make the calculations easier take the acceleration due to gravity as 10 m s 2 10ms^{-2}

Fine I can't find it! I give up! How can it rise! The bullet is travelling horizontally! 3 1 10 5 None of these! because my answer is different! 6

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1 solution

Chew-Seong Cheong
Mar 11, 2015

It is given that:

  • m 1 = m_1 = mass of wooden block = 0.9 k g = 0.9 kg
  • m 2 = m_2 = mass of bullet = 0.1 k g = 0.1 kg
  • v 0 = v_0 = velocity the bullet striking wooden block = 10 m s 1 = 10ms^{-1}
  • g = g = acceleration due to gravity = 10 m s 2 =10ms^{-2}

By conservation of momentum, the velocity of the wooden block and bullet together v 1 v_1 after the bullet strikes the wooden block is given by:

m 2 v 0 = ( m 1 + m 2 ) v 1 0.1 ( 100 ) = ( 0.9 + 0.1 ) v 1 v 1 = 10 m s 1 m_2v_0 = (m_1+m_2)v_1 \quad \Rightarrow 0.1(100) = (0.9+0.1)v_1\quad \Rightarrow v_1 = 10 ms^{-1}

By conservation of energy, we have the height h h the block rises is given by:

1 2 ( m 1 + m 2 ) v 1 2 = ( m 1 + m 2 ) g h \frac {1}{2}(m_1+m_2)v_1^2 = (m_1+m_2)gh

1 2 ( 1 ) ( 100 ) = ( 1 ) ( 10 ) h h = 5 m \Rightarrow \frac {1}{2}(1)(100) = (1)(10)h \quad \Rightarrow h = \boxed{5}m

Perfect! That's what I've expected!

Sravanth C. - 6 years, 3 months ago

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