Gravity Height and gravity

The value of acceleration due to gravity at height of 12,800 km from the surface of the earth is _ _ _ _ _ _ ?

Note:

1) Take acceleration due to gravity as 9.8 m s 2 9.8m{ s }^{ -2 } .

2) Provide the answer up to 2 decimal places.


The answer is 1.09.

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1 solution

Saurabh Patil
Apr 20, 2015

G M R 2 = 9.8 \frac{GM}{R^{2}} = 9.8 G M ( 3 R ) 2 = 9.8 9 = 1.09 \frac{GM}{(3R)^{2}} = \frac{9.8}{9} = 1.09

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