What is the gravitational force acting on a body which is 3200Km above the earth's surface?(answer in m/s^2). Please post the method.
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At the Earth's surface, 6400 km from the center, the acceleration due to gravity is 9 . 8 m / s 2 . Now, we increase the distance from the center by a factor of 1 . 5 , so the gravitational force must be divided by 1 . 5 2 . Therefore, the acceleration due to gravity there is 2 . 2 5 9 . 8 = 4 . 3 6 m / s 2