Gravity and simple pendulum

The motion of the metallic Bob of the Simple Pendulum of length "L" with gravitational acceleration "g" will be slowest at :

Poles Surface of earth Centre of Earth Equator

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1 solution

Jinay Patel
Mar 8, 2014

That's easy, at Centre of Earth gravity is zero.

The frequency of a harmonic pendulum is approximately ω = g / L \omega = \sqrt{g/L} .

Josh Silverman Staff - 7 years, 3 months ago

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