How much below the surface of the Earth does the acceleration due to gravity reduce by 36% of its value on the surface of the Earth.
DETAILS AND ASSUMPTIONS:
1) Take the radius of the Earth as 6400 km.
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Here,
g h = g − 1 0 0 3 6 g = 1 0 0 6 4 g
But, g h = g ( 1 − R d ) or, d = g ( g − g h ) R
g h = g ( g ( g − 1 0 0 6 4 g ) 6 4 0 0 )
d = g ( 1 0 0 1 0 0 − 6 4 × 6 4 0 0 ) = 2 3 0 4 k m