Greatest Number.

The greatest among the numbers, A . 3 1 4 A. 3^\frac{1}{4} B . 4 1 5 B. 4^\frac{1}{5} C . 1 2 1 10 C. 12^\frac{1}{10} D . 1 D. 1

D C A B

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3 solutions

Vivek Vijayan
Jul 16, 2014

Here I will give the solution. first of all we to equalise the nth roots. ie. By taking its LCM(4,5,10). Which is 20. 3 1 4 , 4 1 5 , 1 2 1 10 3^\frac{1}{4} , 4^\frac{1}{5} , 12^\frac{1}{10} becomes, ( 3 5 ) 1 20 , i e . 24 3 1 20 , ( 3^5)^\frac{1}{20} , ie. 243^\frac{1}{20}, and others become 25 6 1 20 , 14 4 1 20 256^\frac{1}{20} , 144^\frac{1}{20} and 1 can be written as 1 1 20 1^\frac{1}{20}

Now it is clearer and easy to find the answer. It is 4 1 5 4^\frac{1}{5} . Hope you understood.

HOW WAS I SUPPOSED TO KNOW THAT THOSE FRACTIONS WERE
EXPONENTS AND NOT JUST FRACTIONS!!!

Nathan Blanco - 6 years, 10 months ago
Parth Bhardwaj
Feb 28, 2015

Raise each of them to the power 20 ( Multiple of their powers - 4,5,10,1). And then compare 243,256,144 and 1 respectively for each term.

Anand Babu Kotha
Jul 16, 2014

n th root of any integer is greater than 1

I don't get it. What do you mean by the "greatest"? I answered C because 12 will always be greater in value compared to the other choices regardless of the fractions :/

Astro Enthusiast - 6 years, 11 months ago

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Its 10th root of 12

Vivek Vijayan - 6 years, 11 months ago

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Oh yah right! Damn. I thought its 12 and 1/10. haha. thank you :D

Astro Enthusiast - 6 years, 11 months ago

Hats off. So how you found out which one among the following is the greatest among the 3 irrational numbers.

Vivek Vijayan - 6 years, 11 months ago

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