Let
be positive real numbers with sum
. Find the maximum value of
This problem is part of this set .
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a=1 b=2 c=3 because the sum of a+b+c=6
then:
1st cube root
a^2=1
2bc=2(2)(3) = 12
1+12=13
cube root of 13 is 2.35
2nd cube root
b^2=4
2ca=2(3)(1)=6
4+ 6=10 cube root of 10 is 2.15
3rd cube root c^2=9 2ab=2(1)(2)=4 9+4=13 cube root of 13=2.35
then add: 2.35+2.15+2.35= 6.85 s=6.85
did i make it easy or complicated?