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Algebra Level 1

If x 2 1 x 2 = 100 x^2 - \dfrac1{x^2} = 100 , what is the relationship between the two numbers,

( x + 1 x ) and ( x 1 x ) ? \left( x + \dfrac1x\right) \ \text{ and } \ \left( x - \dfrac1x \right) \; ?

Their sum is 100 Their absolute difference is 100 Their product is 100 Their ratio is 100

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2 solutions

x 2 1 x 2 = ( x 1 x ) ( x + 1 x ) x^2-\dfrac{1}{x^2}=\left(x-\dfrac{1}{x}\right)\left(x+\dfrac{1}{x}\right)

Stephen Liado
Mar 21, 2016

Recall that x^2-y^2=(x+y)(x-y)

So:

x^2-1/x^2 =100 (x)^2-(1/x)^2=100 (x+1/x)(x-1/x)=100

Therefore, their product is 100.

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