* *let G be a cyclic group of order 60.then the number of subgroup of G is
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A cyclic group of order n has d(n) no.of subgroups. Where,
d(n) = no.of positive divisors of n
Divisors of 60 = 1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30, 60
d(60) = 12