Grouping up Number theory-1

Find the number of positive integers n [ 1 , 100 ] n\in[1,100] for which 3 n 2 n + 1 3| n2^n+1 .


The answer is 34.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Nihar Sarkar
Sep 12, 2018

We check that 2 is congruent to -1 mod 3. Hence we put that in n2^n + 1 and for even n we have 3 divides n + 1. We can easily find there are 17 such n below 100 starting from 2 and in multiples of 6. Again for odd n we use congruence mod 3 to get 3 divide -n + 1 =》 3 divides 2n + 1 then. We then find all these n starting with 1 and incresing in multiples of 6. We get 17 such n again. So no. Of sol. : 17+17 = 34.

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...