Guess the Sum

Logic Level 3

Alan has thought of 2 distinct positive digits, and wants Betty to guess their sum.

Betty: The sum can be from 3 to 17. Can you give me a further hint?
Alan: The last digit of the product of these two digits, is the last digit of your phone number.
Betty: Ah, now I know the sum.

What is the sum of these two numbers?

12 10 13 We do not have enough information 11 16 15 14

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1 solution

Note first that since the sum can be from 3 3 to 17 17 we are dealing with non-zero digits.

For Betty to be sure of what the sum of the two digits is, based on the knowledge of the last digit of the product of the two digits, this last digit must be unique over all products of two digits. Now

  • 2 2 is the last digit in the products 3 × 4 3 \times 4 and 2 × 6 2 \times 6 , among others,

  • 3 3 is the last for 1 × 3 1 \times 3 and 7 × 9 7 \times 9 ,

  • 4 4 is the last for 1 × 2 1 \times 2 and 2 × 7 2 \times 7 ,

  • 5 5 is the last for 3 × 5 3 \times 5 and 5 × 7 5 \times 7 ,

  • 6 6 is the last for 1 × 6 1 \times 6 and 2 × 3 2 \times 3 ,

  • 7 7 is the last for 1 × 7 1 \times 7 and 3 × 9 3 \times 9 ,

  • 8 8 is the last for 2 × 4 2 \times 4 and 6 × 8 6 \times 8 .

However, 1 1 is the last digit for just one product, namely 3 × 7 3 \times 7 , and 9 9 is the last digit for only one product, namely 1 × 9 1 \times 9 . In either case the sum of the digits is 10 10 , so whether the last digit of Betty's phone number is 1 1 or 9 9 , she will be ale to conclude that the sum of Alan's two distinct digits is 10 \boxed{10} .

I found it really interesting that there were 2 possibilities for set of the numbers, and we still don't know what they are :)

Chung Kevin - 4 years, 3 months ago

I did want them to be positive. Sorry, I just added them in.

Chung Kevin - 4 years, 3 months ago

but sir 1 is the last digit for 11 × 1 = 11 11\times 1=11 hence you can exclude the case of 3 × 7 3\times 7 and then we are left with just 1 × 9 1\times 9

Achal Jain - 4 years, 3 months ago

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Yes, 1 is the last digit of 11 × 1 11 \times 1 but 11 11 is not a digit, (positive digits are 1 , 2 , 3 , . . . , 8 , 9 1,2,3,...,8,9 ), so we still need to include 3 × 7 3 \times 7 .

Brian Charlesworth - 4 years, 3 months ago

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thanks sir i forgot the question demanded digits.

Achal Jain - 4 years, 3 months ago

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