Calvin was at his local grocery store, and saw that they had gummy worms for sale. To satisfy his foreseeable sugar craving, he bought 72 bags of gummy worms. Upon exiting the store, he noticed that the ink on the receipt was smudged, and he could see the price as $ _ 3 . 4 _ . What is the price (in cents) of 1 bag of gummy worms?
Details and assumptions
A bag of gummy worms cost a whole number of cents.
The tens digit of the dollars is missing, and the units digit of the cents is missing. The receipt was for less that $100.
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This is a comment written by Ghanashyam. As it is insightful and explains a neat approach to the problem, I have converted it into a solution.
Calvin sir, where in the solution is k ? It is not used anywhere, but still there is "k should be divisible by 8". Please specify!
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It is x or k whatever-same thing. :)
Thanks for pointing that I should define my variables.
k was used to denote the term -34-. I accidentally removed that when I was editing the question.
sir also in the solution, it should read as "sum of digits must be a multiple of 9" and not 8
There is only one multiple of 72 that has 34 in it that is under 10000. It must be under 10000 because it is given that it is under $100. With 7344 being a multiple of 72. $73.44 is the final bill. Because each bag is an equal price you can do 7344/72 which equals 102.
First of all, converting the price into cents, we get 34 cents. Now let x be the price of one bag. Calvin got 72 bags. So 72x = 34 cents. Now we need to find a multiple of 72 which has 3 and 4 as its middle digits. By trail and error, this can be found to be 102, which is the answer. Thus, each bag costs 102 cents
A better method would be as follows:
let the cost per bag be $x.(i have indicated a blank using -)
we have 72x=$-3.4-
let -3.4-=k (for ease of working only)
k should be divisible by 8, so the second blank is 4. k should be divisible by 9, so the first blank is 7. we have k=73.44 thus x=$1.02 or 102 cents!!
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Good observation! I've converted this into an actual solution, so that others can learn from it.
what is the problem with 23.46,33.42,63.42 and many more as the price of 72 bags
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The three amounts that you gave are not valid, as they do not satisfy the condition given in the question, which says-
A bag of gummy worms cost a whole number of cents.
If you divide the numbers given by you into 72 gummy bears, you will not end up with the price of one gummy bear as a whole number. So, the random numbers you generated are invalid.
Hope that helped, Pratyush!
i thought $1= 100cents
1$ = 100 cents
Calvin bought 72 bags,
72x=-34- cents, where x is the cost of one bag of gummy worms.
By trial and error method,
72*102= 7344
Hence one bag of gummy worms cost 102 cents
First, we know that the price of 72 bags of gummy worms is $ 3.4
If x = the tens digit of the dollar and y is the units digit of the cents, the price will be $x3.4y
x34y could be divided by 72, so x34y could be divided by 8 and 9
8 is 2^3 so 34y could be divided by 8, so y is 4
x+3+4+4 could be divided by 9 so x is 7
7344 divided by 72 is 102
1$ = 100 cents
Calvin bought 72 bags,
72x= 34 cents , where x is the cost of one bag of gummy worms.
By trial and error method,
72x102= 7344
Hence one bag of gummy worms cost 102 cents
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A better method would be as follows:
let the cost per bag be x cents.
i have indicated a blank using -
we have 72x cents=$-3.4-
let k = -34- =72x
k should be divisible by 8, so the second blank is 4. (since 344 is a multiple of 8)
k should be divisible by 9, so the first blank is 7. (since sum of digits must be a multiple of 9)
Thus the total is 7344 cents thus x= 102 cents!!