Hail Stewart-1!

Geometry Level 3

In A B C \triangle ABC , A C = B C AC=BC , point D D is on B C BC such that C D = 3 × B D CD=3\times BD , and E E is the midpoint of A D AD such that C E = 7 CE=\sqrt 7 and B E = 3 BE=3 .

If the area of A B C \triangle ABC is m n m\sqrt n , where m m and n n are positive integers and n n is square-free, find m + n m+n .


The answer is 10.

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2 solutions

김 재형
Apr 15, 2018

Heh, I'm the first!!! :D

Since length of all three sides have been found, the area of the triangle can easily be calculated, either through Heron's formula or by using the properties of isosceles triangles. The area is 3*sqrt(7), and since both 3 and 7 are positive integers and n is square-free, m+n = 10.

Bro. Your X and multiple sign is very similar. Use dot for multiplication sign, instead.

Bostang Palaguna - 2 years, 7 months ago

on pic 2 where it says ED^2= what does it say its not clear,is that a 7x or square root 7?

monster muri - 7 months, 1 week ago

Stewart's Theorem

Systems of Equation

Similar Triangles/ Area Ratio

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