Half Gone

Let $b =$ weight of the bottle alone and $g =$ weight of the green tea alone.

Then,

$b + g = 350 g$ and

$b + \frac{1}{2}g = 200 g$ .

Solving for the equations gives us

$b = 50 g$

Half of the tea itself weighs 150g. Subtract it from 200g to get 50g.

350-200=150= the weight of half of the water. 150+150=300=weight of all the water. 350-300=50=50g so therefore, the answer is 50g

Let $b$ be the weight of the empty bottle and $t$ be the weight of the green tea.

$b + t = 350$ $\color{#D61F06}(1)$

$b + \frac{1}{2}t = 200$ $\color{#D61F06}(2)$

Subtracting $\color{#D61F06}(2)$ from $\color{#D61F06}(1)$ , we get

$\frac{1}{2}t = 150$

$t = 300$

Solving for $b$ by substituting $300$ for $t$ in $\color{#D61F06}(1)$ or $\color{#D61F06}(2)$ , we get

$b + 300 = 350$ $\color{#3D99F6}\implies$ $\boxed{\large\color{#20A900}b = 50}$

or

$b + \frac{1}{2}300 = 200$ $\color{#3D99F6}\implies$ $\boxed{\large\color{#20A900}b = 50}$

Given that,

• A full bottle of green tea weighs 350 grams.

• With half the tea consumed, it weighs 200 grams.

Now ,

350 - 200 = 150. 150 is the half of the water so, 200 - 150 = 50 grams is the weight of the empty bottle

bottle+full water (suppose 1)= $350$ gm...............................[1]

bottle+ $\frac{1}{2}$ water = $200$ gm.................................[2]

subtracting [2] from [1] we get,

$bottle +full water(1) -bottle-\frac{1}{2} water$ = $350-200$

or, $\frac{1}{2}$ water= $150$

now,

bottle+ $\frac{1}{2}$ water = $200$ gm.................................[2]

or, bottle+ $150$ = $200$

or,bottle= $50$

so, the empty bottle is 50 gram

(Total empty bottle /w Full green tea)350

-(Total empty bottle /w Half green tea)200

=(Half green tea)150

(Total empty bottle /w Full green tea)350

-(Full green 150X2)300

=(Total empty bottle)50

350-200=150, which is total weight minus the remaining weight which gives the weight of half the tea (I.e. the amount consumed).

150x2=300, which is total weight of the tea.

350-300=50, which is total weight minus the weight of all tea, leaving the weight of the bottle as 50 grams.

Shortcut (as per Lohith's sol'n), once you know the weight of half the tea, subtract it from the remaining weight (I.e. 200-150=50).

Let the weight of the empty bottle be 'X' gms. and the weight of the green tea (in full bottle) be 'Y' gms. Then, according to the problem, we have two equations. X+Y=350; X+Y/2=200 whence we get X=50 gms.

I have no idea what the weight of the bottle is, but its mass seems to be 50 grams.

First we do $350-200=150$ ,then $200-150=\boxed{\large{50}}$

The full bottle was 350 g. The half-full bottle was 200 g. So, 150 g was taken away. To find the empty bottle's weight, you have to subtract 150 g from 200 g.

Here's an easy way I solved it:

I can see that 350g - 250g = 150g. That means that the amount that was drank weight 150g. Since that was half the bottle, we can then subtract 150 from 200 (200-150) and we get the answer, 50g.

We have 2 pieces of information: - A full jar weighs 350g - A half-full jar weighs 200g

The full jar weighs 150g more than the half-full jar. Because of this, we can assume the full liquid is 300g ( $150g \times 2$ )

Thus 350g (full jar) - 300g (full liquid) = 50g. Thus will be the weight of the jar by itself.

Thus the answer is 50g